"""
The Full Whiskas Model Python Formulation for the PuLP Modeller
Authors: Antony Phillips, Dr Stuart Mitchell 2007
"""
# Import PuLP modeler functions
from pulp import *
# Creates a list of the Ingredients
Ingredients = ['CHICKEN', 'BEEF', 'MUTTON', 'RICE', 'WHEAT', 'GEL']
# A dictionary of the costs of each of the Ingredients is created
costs = {'CHICKEN': 0.013,
'BEEF': 0.008,
'MUTTON': 0.010,
'RICE': 0.002,
'WHEAT': 0.005,
'GEL': 0.001}
# A dictionary of the protein percent in each of the Ingredients is created
proteinPercent = {'CHICKEN': 0.100,
'BEEF': 0.200,
'MUTTON': 0.150,
'RICE': 0.000,
'WHEAT': 0.040,
'GEL': 0.000}
# A dictionary of the fat percent in each of the Ingredients is created
fatPercent = {'CHICKEN': 0.080,
'BEEF': 0.100,
'MUTTON': 0.110,
'RICE': 0.010,
'WHEAT': 0.010,
'GEL': 0.000}
# A dictionary of the fibre percent in each of the Ingredients is created
fibrePercent = {'CHICKEN': 0.001,
'BEEF': 0.005,
'MUTTON': 0.003,
'RICE': 0.100,
'WHEAT': 0.150,
'GEL': 0.000}
# A dictionary of the salt percent in each of the Ingredients is created
saltPercent = {'CHICKEN': 0.002,
'BEEF': 0.005,
'MUTTON': 0.007,
'RICE': 0.002,
'WHEAT': 0.008,
'GEL': 0.000}
# Create the 'prob' variable to contain the problem data
prob = LpProblem("The Whiskas Problem", LpMinimize)
# A dictionary called 'ingredient_vars' is created to contain the referenced Variables
ingredient_vars = LpVariable.dicts("Ingr",Ingredients,0)
# The objective function is added to 'prob' first
prob += lpSum([costs[i]*ingredient_vars[i] for i in Ingredients]), "Total Cost of Ingredients per can"
# The five constraints are added to 'prob'
prob += lpSum([ingredient_vars[i] for i in Ingredients]) == 100, "PercentagesSum"
prob += lpSum([proteinPercent[i] * ingredient_vars[i] for i in Ingredients]) >= 8.0, "ProteinRequirement"
prob += lpSum([fatPercent[i] * ingredient_vars[i] for i in Ingredients]) >= 6.0, "FatRequirement"
prob += lpSum([fibrePercent[i] * ingredient_vars[i] for i in Ingredients]) <= 2.0, "FibreRequirement"
prob += lpSum([saltPercent[i] * ingredient_vars[i] for i in Ingredients]) <= 0.4, "SaltRequirement"
# The problem data is written to an .lp file
prob.writeLP("WhiskasModel2.lp")
# The problem is solved using PuLP's choice of Solver
prob.solve()
# The status of the solution is printed to the screen
print "Status:", LpStatus[prob.status]
# Each of the variables is printed with it's resolved optimum value
for v in prob.variables():
print v.name, "=", v.varValue
# The optimised objective function value is printed to the screen
print "Total Cost of Ingredients per can = ", value(prob.objective)